SOLUTION: .............Lead....Zink....Copper Alloy A..40%...30%...30% Alloy B..20%...30%...50% Alloy C..........10%...90% How many grams of each alloys A, B, and C must be mixed to ge

Question 353765: .............Lead....Zink....Copper
Alloy A..40%...30%...30%
Alloy B..20%...30%...50%
Alloy C..........10%...90%
How many grams of each alloys A, B, and C must be mixed to get 325g of an alloy that is 15.2% lead, 37.2% zink, and 47.6% copper?
I've tried this using the Matrix, and the inverse Matrix, and keep coming up with negitives on some alloys.
Thanks for your help.
Neil
Found 2 solutions by Fombitz, scott8148:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let be the amount of alloy A, alloy B, alloy C.
.
.
.
Lead:
Zinc:
Copper:
.
.
.

Using matrix inversion,

.
.

.
.
.
I get the same answer.
Something is up with the problem setup.

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(40)(A) + (20)(B) + (0)(C) = (15.2)(325)

(30)(A) + (30)(B) + (10)(C) = (37.2)(325)

(30)(A) + (50)(B) + (90)(C) = (47.6)(325)
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