SOLUTION: 40 oz of a 35% gold alloy are mixed with 52 oz of a 26% alloy. Find the concentration of the resulting gold alloy.
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Question 352062: 40 oz of a 35% gold alloy are mixed with 52 oz of a 26% alloy. Find the concentration of the resulting gold alloy.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
40 oz of a 35% gold alloy
52 oz of a 26% alloy.
Total mix = 40+52= 92 oz.
35*40+52*26=92*x
1400+1352 =92x
x=29.9 % = 30%
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