# SOLUTION: A solution of 70% alcohol is to be mixed with a solution of 34% alcohol to form 72 liters of a 47% solution. How many liters of the 70% solution must be used? NEED HELP ASAP!

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 Question 351479: A solution of 70% alcohol is to be mixed with a solution of 34% alcohol to form 72 liters of a 47% solution. How many liters of the 70% solution must be used? NEED HELP ASAP!Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website!Hi, Let x be the total amount of the 70% alcohol solution. then (72L -x) would be the total amount of the 34% alcoohol solution. . question states: .70*x + .34*(72L-x) = .47*72 . simplify and solve .70*x + .34*72L- .34*x = .47*72L .36*x = .47*72L - .34*72L .36x = 9.36L x = 26L (the amount of the 70% alcohol solution needed to be used)