# SOLUTION: 5. A chemist has one solution that is 15% acid and another solution that is 25% acid. How much of the 15% solution is needed to make 100 L of a solution that is 18% acid? a. 45

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 Click here to see ALL problems on Mixture Word Problems Question 351038: 5. A chemist has one solution that is 15% acid and another solution that is 25% acid. How much of the 15% solution is needed to make 100 L of a solution that is 18% acid? a. 45 L b. 70 L c. 25 L d. 30 LFound 2 solutions by Alan3354, stanbon:Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!A chemist has one solution that is 15% acid and another solution that is 25% acid. How much of the 15% solution is needed to make 100 L of a solution that is 18% acid? ------------ f = amount of 15% t = amount of 25% ---------- f + t = 100 (total solution) 0.15f + 0.25t = 0.18*100 (total acid) You can finish it. Answer by stanbon(57395)   (Show Source): You can put this solution on YOUR website!A chemist has one solution that is 15% acid and another solution that is 25% acid. How much of the 15% solution is needed to make 100 L of a solution that is 18% acid? ------------------------ Equation: acid + acid = acid 0.15x + 0.25(100-x) = 0.18*100 L --------------------------------------------- Multiply thru by 100 to get: 15x + 2500-25x = 1800 --- -10x = -700 x = 70 L (amt of 15% solution needed for the mixture) --- 100-x = 30L (amt of 25% solution needed for the mixture) ==================================== Cheers, Stan H. a. 45 L b. 70 L c. 25 L d. 30 L