You can put this solution on YOUR website!
I assume you are the student who sent the "Carrier to Guam" problem,
the only way I can contact you is by editing this problem;
A submarine left Hawaii two hours before an aircraft carrier.
The vessels traveled in opposite directions.
The aircraft carrier traveled at 25 mph for nine hours.
After this time the vessels were 280 miles apart.
Find the submarine’s speed.
Let r = submarines speed
Since they travel in opposite directions, their speeds are additive
Since the sub left 2 hrs early, it traveled for 11 hrs while the carrier traveled 9 hrs
Write a distance equation; dist = r*t
Sub dist + Carrier dist = 280
11r + 9(25) = 280
11r + 225 = 280
11r = 280 - 225
11r = 55
r = 55/11
r = 5 mph is the speed of the sub
Check this in the distance equation
11*5 = 9*25 = 280
Let me know if you get this, please
An aircraft carrier made a trip to Guam and back.
The trip there took three hours and the trip back took four hours.
It averaged 6 km/h on the return trip. Find the average speed of the trip there.
Let s = speed to Guam
Write a distance equation; dist = speed * time
Trip there = Tip back
3s = 6*4
3s = 24
s = 8 km/hr there