SOLUTION: How much of a 60%-acid solution must be mixed with 70 gallons of a 16%-acid solution to obtain a
solution that is 50% acid?
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Question 341135: How much of a 60%-acid solution must be mixed with 70 gallons of a 16%-acid solution to obtain a
solution that is 50% acid?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How much of a 60%-acid solution must be mixed with 70 gallons of a 16%-acid solution to obtain a solution that is 50% acid?
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Equation:
acid + acid = acid
0.16*70 + 0.60x = 0.50(70+x)
Multiply thru by 100 to get:
16*70 + 60x = 50*70 + 50x
10x = 34*70
x = 34*7
x = 238 gallons (amt of 60% solution needed for the mixture)
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Cheers,
Stan H.
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