SOLUTION: what quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 ml of a 45% solution?

Question 338635: what quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 ml of a 45% solution?
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What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 mL of a 40% solution?
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s = 75% acid volume
t = 25% acid volume
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s + t = 500
0.75s + 0.25t = 0.4*500 = 200 --> x4
3s + t = 800
1s + t = 500
-------------- Subtract
2s = 300
s = 150 ml of 75%
t = 350 ml of 25%

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