SOLUTION: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? I need to translate this problem int

Question 334816: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? I need to translate this problem into a pair of linear equations in two variables. Can anyone help?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let A be the number of liters of 40%-alcohol solution.
Look at the concentration equation.

.
.
.
10 liters of 40% solution plus 10 liters of 80% will provide 20 liters of 60% solution.

RELATED QUESTIONS
How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by RAY100)

How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by ankor@dixie-net.com)

how many liters of a 40% alcohol solution must be mixed with 10 liters of a solution... (answered by Alan3354)

How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by checkley77)

How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by nyc_function)

how many liters of a 10 percent alcohol solution must be mixed with 70 liters of the... (answered by mananth)

how many liters of a 10% alcohol solution must be mixed with how many liters of a 50%... (answered by mananth)

How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by Fombitz,edjones)

How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by richwmiller)

how many liters of a 20% alcohol solution must be mixed with 30 liters of a 80% solution... (answered by robertb)