# SOLUTION: A chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration?

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 Click here to see ALL problems on Mixture Word Problems Question 333345: A chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration?Found 2 solutions by stanbon, mananth:Answer by stanbon(57984)   (Show Source): You can put this solution on YOUR website!A chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration? --------------- Equations: Quantity: x + y = 10L Quality: 0.35x + 0.50y = 0.40*10 ------------------------------------- Multiply thru 1st by 25 Multiply thru 2nd by 100 ------------------------------- Quantity: 35x + 35y = 35*10 Quality: 35x + 50y = 40*10 --------------------------------- Subtract Quantity from Quality to get: 15y = 5*10 y = 3 1/3 L (amt of 50% NaCl needed in the mixture) --- Solve for "x": x = 10- 3 1/3 = 6 2/3 L (amt of 35% NaCl needed in the mixture) =============== Cheers, Stan H. Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!35% NaCl solution let this be x L 50% NaCl solution. this will be 10-x mix to get 40% 10 L .. 0.35x+0.5(10-x)=0.4*10 0.35x+5-0.5x=4 -0.15x=-1 x=-1/0.15 = 6.66 L 35% solution Balance 3.34 L will be 50% solution CHECK 6.66*35+3.34*50 = 40*10