SOLUTION: What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 810 mL of a 50 per cent solution?

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 Click here to see ALL problems on Mixture Word Problems Question 331082: What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 810 mL of a 50 per cent solution? Answer by stanbon(57224)   (Show Source): You can put this solution on YOUR website!What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 810 mL of a 50 per cent solution? ---------------- acid + acid = acid 0.75x + 0.30(810-x) = 0.50*810 --- Multiply thru by 100 to get: 75x + 30*910 - 30x = 50*810 45x = 20*810 x = (4/9)(810) x = 4*90 x = 360 mL (amt. of 75% solution needed for the mixture) ============================ Cheers, Stan H.