SOLUTION: Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 800 mL of a solution that is 60 % alcohol. How much of each solution should you use?

Algebra.Com
Question 327775: Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 800 mL of a solution that is 60 % alcohol. How much of each solution should you use?
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
.80x+.30(800-x)=.60*800
.80x+240-.30x=480
.50x=480-240
.50x=240
x=240/.5
x=480 ml of 80% solution is used.
800-480=320 ml of 30% solution is used.
Proof:
.80*480+.30*320=.60*800
384+96=480
480=480

RELATED QUESTIONS

I'm struggling a bit with word problems and mixtures that contain percentages. Maybe you (answered by ankor@dixie-net.com,richwmiller)
Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 800mL of a (answered by ptaylor)
1.Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 725... (answered by solver91311,josgarithmetic,greenestamps)
Solution A is 30% alcohol and solution B is 60% alcohol. How much of each is needed to... (answered by Alan3354)
Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 800mL of a (answered by ankor@dixie-net.com)
Mix a solution that is 40% alcohol with a solution that is 10% alcohol to make 225 mL of... (answered by rwm)
A lab assistant is asked to mix a 30% alcohol solution with 21 liters of an 80% alcohol... (answered by ewatrrr)
System of equations: A laboratory assistant is asked to mix 30% alcohol solution with... (answered by josmiceli)
Becky makes an antiseptic of alcohol and water. If she buys a solution that is 40%... (answered by jorel555)