SOLUTION: a pharmacist has 20 L of a 10% drug solution. How many liters of 5% solution must be added to get a mixture that is 8% ?

Algebra.Com
Question 316114: a pharmacist has 20 L of a 10% drug solution. How many liters of 5% solution must be added to get a mixture that is 8% ?

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
a pharmacist has 20 L of a 10% drug solution. How many liters of 5% solution must be added to get a mixture that is 8% ?
.
Let x= liters of 5% solution added
then
.05x + .10(20) = .08(20+x)
.05x + 2 = 1.6+.08x
2 = 1.6+.08x
.4 = .08x
5 liters = x

RELATED QUESTIONS

A pharmacist has 20 L of a 10% drug solution. How many liters of 5% solution must be... (answered by Fombitz)
a pharmacist has 20 L of a 10% drug solution. how many liters of 5% drug solution must be (answered by josgarithmetic)
a pharmacist has 20 liters of a 10% drug solution how many liters of 5% solution must be... (answered by josgarithmetic)
A pharmacist has 20 liters of a 10% drug solution. How many liters of 5% solution must be (answered by josgarithmetic)
A pharmacist has 20 liters of a 5% drug solution. How many Liters of 10% solution must be (answered by josgarithmetic)
A pharmacist has 20L of a 10% drug solution. How many liters of 5% solution must be... (answered by ankor@dixie-net.com)
Please help me solve this problem...A pharmacist has 20% of a 10% drug solution. How many (answered by richwmiller)
if a pharmacist has 20L of a 10% drug solution. How many liters of 5$ solution must be... (answered by stanbon)
A pharmacist had a 12% solution and a 5% solution. How much of each must be used to get a (answered by solver91311)