SOLUTION: If an object is propelled upward from a height of 96 feet at an initial velocity of 80 feet per second,then its height after t seconds is given by the equation h= -16t^2+80t+96 whe

Question 315125: If an object is propelled upward from a height of 96 feet at an initial velocity of 80 feet per second,then its height after t seconds is given by the equation h= -16t^2+80t+96 where h is in feet. After how many seconds will the object reach a height of 196 feet.
Answer by malaydassharma(59) (Show Source): You can put this solution on YOUR website!

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Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored:

Again, the answer is: 2.5, 2.5. Here's your graph:

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