SOLUTION: 62(200 Solution A is 80% Alcohol and Solution B is 30% Alcohol. How many Liters of each Solutions should be mixed in order to make 200 liters of a Solution that is 62% Alcohol ?

Question 313284: 62(200
Solution A is 80% Alcohol and Solution B is 30% Alcohol. How many Liters of each Solutions should be mixed in order to make 200 liters of a Solution that is 62% Alcohol ?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
1.
2.
Multiply eq.2 by and add the equations together.

Then from eq. 2,

128 liters of 80% solution and 72% of the 30% solution.
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