SOLUTION: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution
to get a 20% solution?
Algebra.Com
Question 310597: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution
to get a 20% solution?
Found 2 solutions by Fombitz, modi.kk91:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let X be the liters of 10% solution.
300 liters of 10% solution.
Answer by modi.kk91(20) (Show Source): You can put this solution on YOUR website!
10% 80%
20%
80-20=60 20-10=10
ratio=6:1
6:1::x:50
x=300liter
RELATED QUESTIONS
how many liters of a 10% alcohol solution must be mixed with how many liters of a 50%... (answered by mananth)
How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by Fombitz,edjones)
How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by richwmiller)
How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution... (answered by mtmorro)
how many liters of a 10% alcohol solution must be mixed with 60 liters of a 50% solution... (answered by Fombitz)
how many liters of a 10% alcohol solution must be mixed with 90 liters of a 50% solution... (answered by Fombitz)
How many liters of a 14 percent Alcohol Solution must be mixed with 20 liters of a 50... (answered by ewatrrr)
how many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by mukhopadhyay)
how many liters of 20% alcohol soltuion must be mixed with 10 liters of a 50% solution to (answered by Alan3354)