# SOLUTION: how many quarts of a solution with 18% iodine must be added to 40 quarts of water to have a resulting solution with 10% iodine? Can somebody please explain me in details without

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how many quarts of a solution with 18% iodine must be added to 40 quarts of water to have a resulting solution with 10% iodine? Can somebody please explain me in details without      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Mixtures Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Mixture Word Problems Question 308870: how many quarts of a solution with 18% iodine must be added to 40 quarts of water to have a resulting solution with 10% iodine? Can somebody please explain me in details without any Shortcuts:/Answer by stanbon(57377)   (Show Source): You can put this solution on YOUR website!how many quarts of a solution with 18% iodine must be added to 40 quarts of water to have a resulting solution with 10% iodine? Can somebody please explain me in details without any Shortcuts:/ -------------- Equation: iodine + iodine = iodine 0.18x + 0*40 = 0.10(x+40) --- Multiply thru by 100 to get: 18x + 0 = 10x + 10*40 8x = 10*40 x = 10*5 x = 50 quarts (amt. of 18% solution needed in the mixture) ======================== Cheers, Stan H.