SOLUTION: If a container contains a mixture of 5 gallons of white paint and 11 gallons of brown paint, how much white paint must be added to the container so that the new mixture will be two

Question 308654: If a container contains a mixture of 5 gallons of white paint and 11 gallons of brown paint, how much white paint must be added to the container so that the new mixture will be two-thirds white paint?
choices:
a:) 16gal
b:) 17gal
c:) 18gal
d:) 19gal
Found 2 solutions by rapaljer, stanbon:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x= amount of white paint to be added
5+x = total amount of white paint
16+x = total amount of paint in the container

Since means that
means that

gallons of white paint to be added

Check: White paint = 5+17=22 gallons
Total paint = 16+17= 33 gallons. So, 22/33 = 2/3 white paint.

Final answer is B) 17 gallons.

Dr. Robert J. Rapalje, Retired
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If a container contains a mixture of 5 gallons of white paint and 11 gallons of brown paint, how much white paint must be added to the container so that the new mixture will be two-thirds white paint?
--------------
Equation:
white + white = white
5 + x = (2/3)(x+16)
(1/3)x = (2/3)16 - 5
x = 17 gallons (amt. of white paint needed for the mixture)
======================
Cheers,
Stan H.
======================

choices:
a:) 16gal
b:) 17gal
c:) 18gal
d:) 19gal

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