SOLUTION: A 2% solution of sulfuric acid was mixed with a 12% solution of sulfuric acid to produce an 8% solution. Determine how much 2% solution and how much 12% solution were used to produ

Algebra.Com
Question 295833: A 2% solution of sulfuric acid was mixed with a 12% solution of sulfuric acid to produce an 8% solution. Determine how much 2% solution and how much 12% solution were used to produce 10 gallons of 8% solution. Enter the amount of 2% solution in the answer box below.
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
.02x+.12y=.08(10)
x+y=10
x=4 y=6
4 gallons of 2%

RELATED QUESTIONS

A 3% solution of sulfuric acid was mixed with an 18% solution of sulfuric acid to produce (answered by checkley79)
How many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24%... (answered by nerdybill)
how many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24%... (answered by mananth)
A 3% solution of sulfuric acid was mixed with an 18% solution to produce an 8% solution.... (answered by checkley77)
Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to... (answered by Alan3354)
A 50%sulfuric acid solution is to be mixed with a 75% sulfuric acid solution to get 60... (answered by josmiceli)
how many grams of a 20% sulfuric acid solution must be mixed with 20 grams of a 35%... (answered by alicealc)
How many milliliters of water must be mixed with 26 milliliters of a 34% sulfuric acid... (answered by josgarithmetic,MathTherapy)
In chemistry class, Todd Corbin has 1 liter of a 20% sulfuric acid solution. How much of... (answered by jorel1380)