SOLUTION: Could somebody please explain to me *clearly* how to solve mixture problems? I've been trying to figure them out, but I just don't understand all of it. For example, how would you
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Question 283890: Could somebody please explain to me *clearly* how to solve mixture problems? I've been trying to figure them out, but I just don't understand all of it. For example, how would you set up an equation for a problem like this?
2.) Brianna has 2 pounds of brand 176 nuts that sell for $3 a pound. She also has brand 391 nuts that sell for $1.74 a pound. If she wants a mixture of nuts that sell for $2.58 a pound, how many pounds of brand 391 should she add?
How do you come to that conclusion?
Please help! :)
Found 3 solutions by richwmiller, Alan3354, solver91311:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
First of all the brand names are only going to lead to confusion so let's change that.
let call brand 391 t for three
and brand 176 o for one
what do we know?
brand o sells for $3.00 lb
and she has 2 lbs of brand o so o=2
brand t sells for 1.74 lb
but we don't know how much she has of brand t . We will call it t
We want to sell a mix (o+t) for 2.58.
So how do we set up an equation?
the individual nuts have to be equal to the mix
What do we want to know?How many lbs of t are we mixing with o
to get o+t
so we are dealing with selling price.
the o selling price is
2*o where o =300
I am going to convert everything to cents so we don't deal with decimals.
2*300+t*174=(2+t)*258
solve for t
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Brianna has 2 pounds of brand 176 nuts that sell for $3 a pound. She also has brand 391 nuts that sell for $1.74 a pound. If she wants a mixture of nuts that sell for $2.58 a pound, how many pounds of brand 391 should she add?
How do you come to that conclusion?
------------------------
B1 costs 300/pound
B3 costs 174/pound
She has 2 pounds of B1
x = pounds of B3 to add
------------------------
The cost of the mix is:
B1*300 + x*174
The amount of the mix is B1 + x
and the cost of the mix is (B1 + x)*258
-----------------
There are 2 equations for the price of the mix, and they're equal
B1*300 + x*174 = (B1 + x)*258
B1 is 2
600 + 174x = 516 + 258x
x = 1 pound
email via the Thank You note if that's not clear, or to Moral Loophole@aol.com
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the number of pounds of the inexpensive brand.
Then the value of the expensive brand is 2 lbs times $3.00 per pound is $6.00. The value of the inexpensive brand is 
. The total weight of the mixture when all is said and done is 
lbs., and the total value of the mixture has to be )
. The sum of the values of the constituent parts of the mixture has to be equal to the total value of the mixture, so:
)
Just solve for
John
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