SOLUTION: A radiator contains 10 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 55% antifreeze? (R
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Question 268025: A radiator contains 10 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 55% antifreeze? (Round your answer to two decimal places.)
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
In words:
(antifreeze started out with - antifreeze removed + antifreeze added)/(total amout of fluid finally in radiator) = 55%
Let = amount of fluid to be drained
given:
Radiator started with:
quarts of fluid
quarts antifreeze
= quarts antifreeze drained
= quarts of pure antifreeze added
-----------------------------------------
(Note that radiator stated with quarts and ended with quarts)
2.4 quarts of fluid must be drained and replaced with pure antifreeze
check answer:
OK
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