SOLUTION: There were 411 people at a play. Admission was $1.00 for adults and $.75 for children. The receipts were $395.75. How many adults and how many children attended?
Algebra.Com
Question 264135: There were 411 people at a play. Admission was $1.00 for adults and $.75 for children. The receipts were $395.75. How many adults and how many children attended?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
A+C=411 OR A=411-C
1A+.75C=395.75
411-C+.75C=395.75
-.25C=395.75-411
.25C=15.25
C=15.25/.25
C=61 CHILDREN TICKETS WERE SOLD.
A=411-61
A=350 ADULT TICKETS WERE SOLD.
PROOF:
350+.75*61=395.75
350+45.75=395.75
395.75=395.75
RELATED QUESTIONS
there were 620 people at a play. The admission was $2 for adults and $1 for children. The (answered by josgarithmetic)
There were 360 people at a play. The admission price was $2 for adults and $1 for... (answered by ewatrrr)
There were 590 people at play. the admission price was $3.00 for adults and $1.00 for... (answered by Jstrasner)
here were 429 people at a play. Admission was S1 each for adults and 75
cents each for... (answered by Alan3354,MathTherapy,greenestamps)
Solve the problem. There were 420 people at a play. The admission price was $2 for adults (answered by lynnlo)
There were 430 people at a play. The admission price was $3 for adults and $1 for... (answered by stanbon)
There were 510 people at a play. The admission price was 2 for adults and 1 for children. (answered by Maths68)
There were 610 people at a play. The admission price was 2$ for adults and 1$ for... (answered by chana)
There were 460 people at a play. The admission price was $3 for adults and $1 for... (answered by Cromlix)