SOLUTION: A silversmith mixed 30 g of a 70% silver alloy with 50 g of a 15% silver alloy. What is the percent concentration of the resulting alloy? (Round your answer to the nearest tenth of

Question 263434: A silversmith mixed 30 g of a 70% silver alloy with 50 g of a 15% silver alloy. What is the percent concentration of the resulting alloy? (Round your answer to the nearest tenth of a percent.)
Found 2 solutions by Alan3354, drk:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A silversmith mixed 30 g of a 70% silver alloy with 50 g of a 15% silver alloy. What is the percent concentration of the resulting alloy? (Round your answer to the nearest tenth of a percent.)
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30*0.7 + 50*0.15 = 80x
80x = 21 + 7.5 = 28.5
x = 0.35625
x = 35.6% Ag
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
This is a mixture problem with out mixture information. Here is a table based on the given information
alloy . . . . . .% . . . . . .g . . . . . . .%g
70 . . . . . . . 70 . . . . 30 . . . . . .2100
15 . . . . . . .15 . . . . .50 . . . . . .750
mix . . . . . . x . . . . . .80 . . . . . .80x
looking at the third column, we get

adding we get

dividing, we get
x = 35.625
which is
35.63% = 35.6%
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