SOLUTION: Crazy Chris has a 1% alcohol solution mix with a 12.5% alcohol solution. He wants 500 mL of 2.5% alcohol. How much of each does he need to mix? LOst.

Question 26088: Crazy Chris has a 1% alcohol solution mix with a 12.5% alcohol solution. He wants 500 mL of 2.5% alcohol. How much of each does he need to mix?
LOst.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let "x" be the amount of 1% solution.
Then "500-x" is the amount of 12.5% solution.
EQUATION:
Follow the acid:
1%x + 12.5%(500-x)=2.5%(500)
Multiply by 1000 to get rid of the % and decimals:
10x+125(500-x)=25(500)
10x+62500-125x=12500
-115x=-50000
x=434.7 mL (You need to have 434.7 mL of 1% solution)
500-x=65.3 mL (You need 65.3 mL of 12.5% solution)
RELATED QUESTIONS
John wants to make a 100 ml of 5% alcohol solution mixing a quantity of 2% alcohol... (answered by greenestamps)

Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10%... (answered by josgarithmetic,MathTherapy)

Alcohol solutions. Gus has on hand a 5% alcohol solution and a 20% alcohol solution. He... (answered by richwmiller)

A chemist wants to mix 10% alcohol solution and a 20% alcohol solution to make a 12%... (answered by ikleyn)

1.Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 725... (answered by solver91311,josgarithmetic,greenestamps)

How would you solve a mixture problem, for example. John wants to make a 100 ml of 5%... (answered by rfer)

A chemist wants to mix a 5% alcohol solution with a 25% alcohol solution to obtain 8... (answered by checkley77)

greg has two soulutions avaiable in a lAB, one with 6% alcohol and another with 14%... (answered by mananth)

Gus has on hand 5% alcohol solution and a 20% alcohol solution. He needs 30 liters of 10% (answered by josmiceli)