# SOLUTION: A chemist needs to mix a solution that is 34% silver nitrate with one that is 4% silver nitrate to obtain 100 milliliters of a mixture that is 7% silver nitrate. How many millilite

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 Click here to see ALL problems on Mixture Word Problems Question 254408: A chemist needs to mix a solution that is 34% silver nitrate with one that is 4% silver nitrate to obtain 100 milliliters of a mixture that is 7% silver nitrate. How many milliliter of each of the solutions must be used?Found 2 solutions by ankor@dixie-net.com, checkley77:Answer by ankor@dixie-net.com(15639)   (Show Source): You can put this solution on YOUR website!A chemist needs to mix a solution that is 34% silver nitrate with one that is 4% silver nitrate to obtain 100 milliliters of a mixture that is 7% silver nitrate. How many milliliter of each of the solutions must be used? : Let x = amt of 34% solution required It states that the resulting amt is to be 100 ml, therefore (100-x) = amt 4% solution : Write an "amt of silver nitrate" equation .34x + .04(100-x) = .07(100) : .34x + 4 - .04x = 7 .34x - .04x = 7 - 4 .3x = 3 x = x = 10 ml of 34% solution and 100 - 10 = 90 ml of 4% solution ; : Check solution: .34(10) + .04(90) = .07(100) 3.4 + 3.6 = 7 Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!.34x+.04(100-x)=.07*100 .34x+4-.04x=7 .30x=7-4 .30x=3 x=3/.30 x=10 ml. of 34% solution is used. 100-10=90 ml. of 3% solution is used. Proof: .34*10+.04*90=7 3.4+3.6=7 7=7