SOLUTION: Can you explain how to do mixture formulas such as: How many liters of 30% alcohol must be mixed with 20 liters of 80% alcohol to obtain a 50% alcohol solution?

Question 250710: Can you explain how to do mixture formulas such as:
How many liters of 30% alcohol must be mixed with 20 liters of 80% alcohol to obtain a 50% alcohol solution?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
http://www.purplemath.com/modules/mixture.htm
In this case
.30x+.80*20=.50(x+20)
The trick here is that we don't know the total amount of solution in the end.
But we do know how much 80 % solution there is.
So we will add x amount so the total will be (20 + x)
Solve the equation will give you x-- the amount of 30% to be added
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