SOLUTION: how many milligrams of metal that contains 45% nickel must be combined of 6 milligrams of 100% nickel to get 78% nickel

Question 250376: how many milligrams of metal that contains 45% nickel must be combined of 6 milligrams of 100% nickel to get 78% nickel
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
This is a mixture problem. Here is the table:
nickel . . . . . % . . . . .mg . . . . . %g
45 . . . . . . .45 . . . . .g . . . . . 45g
100 . . . . . . 100 . . . . 6 . . . . . 600
Mixture . . .. .78 . . . . g + 6 . . . .78g + 468
Now, in the right hand column,
45g + 600 = 78g + 468
33g = 132
g = 4.
4 mg of metal at 45%.

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