SOLUTION: 1. How many gallons of a 10% solution. Would need to be added to a 20% solution to obtain 50 gallons of a 30% solution?
2.How many gallons of milk containing 4% fat is mixed wi
Algebra.Com
Question 249770: 1. How many gallons of a 10% solution. Would need to be added to a 20% solution to obtain 50 gallons of a 30% solution?
2.How many gallons of milk containing 4% fat is mixed with milk containg 1% fat to obtain a 15 gallon mixture containing 2% fat?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1. How many gallons of a 10% solution. Would need to be added to a 20% solution to obtain 50 gallons of a 30% solution?
It's not possible. Adding 10% to 20% will reduce the concentration.
Any mix of 2 concentrations will always result in a %age between the two.
-------------------
2.How many gallons of milk containing 4% fat is mixed with milk containg 1% fat to obtain a 15 gallon mixture containing 2% fat?
0.04*x + 0.01*(15-x) = 0.02*15
4x + 15-x = 30
x = 5 gallons of 4%
10 gallons of 1%
RELATED QUESTIONS
How many gallons of a 60% solution of nitric acid should be added to 10 gallons of a 30%... (answered by josgarithmetic)
How many gallons of a 10% salt solution should be added to 20 gallons of a 60% salt... (answered by checkley77,dabanfield)
How many gallons of a 10% salt solution should be added to 20 gallons of a 60% salt... (answered by addingup)
How many gallons of a 10% salt solution should be added to 20 gallons of a 60% salt... (answered by ikleyn)
How many gallons of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol... (answered by sachi)
How many gallons of a 50% saltwater solution must be added to 10 gallons of a 15%... (answered by stanbon,addingup)
How many gallons of a 10% salt solution must be added to a 15 gallons of a 20% salt... (answered by josmiceli)
How many gallons of a 10% salt solution must be mixed with a 50 gallons of a 50% salt... (answered by rwm)
How many gallons of a 10% salt solution must be mixed with 50 gallons of a 50% salt... (answered by Boreal)