# SOLUTION: How many gallons of a 30 percent alcohol solution must be mixed with 10 gallons of a 50 percent alcohol solution to make a 40 percent alcohol solution? The equation is ((( Amount

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 Click here to see ALL problems on Mixture Word Problems Question 24730: How many gallons of a 30 percent alcohol solution must be mixed with 10 gallons of a 50 percent alcohol solution to make a 40 percent alcohol solution? The equation is ((( Amount x Concentration = Quantity)))Answer by Paul(988)   (Show Source): You can put this solution on YOUR website! Since 30% = 30x Since 10 gallon of 50% = 50(10-x) Total = 40(10) Add it together: 30x+50(10-x)=40(10) 30x+500-50x=400 -20x=-100 x = 5 Hence, there should be about 5 gallons of 30%. Paul.