# SOLUTION: How many pounds of coffee beans selling for \$2.00 per pound should be mixed with 6 pounds of coffee beans selling for \$2.80 per pound to obtain a mixture selling for \$2.48 per poun

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 Question 24135: How many pounds of coffee beans selling for \$2.00 per pound should be mixed with 6 pounds of coffee beans selling for \$2.80 per pound to obtain a mixture selling for \$2.48 per pound.Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Let x = the number of lbs of coffee selling for \$2.00/lb. You want to mix x lbs of \$2.00 coffee beans with 6 lbs of \$2.80 coffee beans to obtain a mixture of (6+x) lbs of \$2.48 coffee beans. Let's set up the appropriate equation to solve this mystery: Simplify and solve for x. Subtract 2x from both sides of the equation. Subtract 14.88 from both sides. Finally, divide both sides by 0.48 You will need to mix 4 lbs of the \$2.00 coffee beans with 6 lbs of the \$2.80 coffee beans to obtain 10 lbs of \$2.48 coffee bean mixture.