SOLUTION: How many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution?
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Question 238189: How many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.20x+.10(50-x)=.12*50
.20x+5-.10x=6
.10x=6-5
.10x=1
x=1/.1
x=10 liters of 20% alcohol is used.
50-10=40 liters of 10% alcohol is used.
Proof:
.20*10+.10*40=.12*50
2+4=6
6=6
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