SOLUTION: how many gallons of 70% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 60% antifreeze
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Question 236010: how many gallons of 70% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 60% antifreeze
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.70x+.10*60=.60(x+60)
.70x+6=.60x+36
.70x-.60x=36-6
.10x=30
x=30/.10
x=300 gal. of 70% anti freeze is used.
Proof;
.70*300+.10*60=.60*(300+60)
210+6=.60*360
216=216
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