You can
put this solution on YOUR website!Let

= grams of 45% mixture to be used
Let

= grams of 75% mixture to be used
given:
(1)

grams
(2)

= pure nickel in final mixture
------------------------------
In words:
( grams of pure nickel in final mixture )/(total grams) = 65%

(3)

Multiply both sides of (1) by

and subtract
(1) from (3)
(3)

(1)

And, since

20 grams of the 45% mixture and 40 grams of the 75% mixture are needed
check:

OK