SOLUTION: A photographer wishes to mix 2 liters of a 5% acetic acid solution with a 10% solution to get a 7% solution. How many liters of the 10% solution must be added?
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Question 232610: A photographer wishes to mix 2 liters of a 5% acetic acid solution with a 10% solution to get a 7% solution. How many liters of the 10% solution must be added?
Thanks so much for your help!
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.10x+.05*2=.07(x+5)
.10x+.1=.07x+.35
.10x-.07x=.35-.1
.03x=.25
x=.25/.03
x=8.333 Liters of 10% acid is used.
Proof:
.10*8.333+.05*2=.07(8.333+5)
.8333+.1=.07*13.333
.9333=.9333
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