SOLUTION: I have been working on this problem all night please help? How many liters of a 20% salt solution must be mixed with 30 liters of an 60% salt solution to obtain a 30% salt solut

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: I have been working on this problem all night please help? How many liters of a 20% salt solution must be mixed with 30 liters of an 60% salt solution to obtain a 30% salt solut      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   


Question 231931: I have been working on this problem all night please help?
How many liters of a 20% salt solution must be mixed with 30 liters of an 60% salt solution to obtain a 30% salt solution?

Answer by ankor@dixie-net.com(15622) About Me  (Show Source):
You can put this solution on YOUR website!
How many liters of a 20% salt solution must be mixed with 30 liters of an 60%
salt solution to obtain a 30% salt solution?
:
Let x = amt of 20% solution required
:
Write an amt of salt equation using the decimal equiv
.20x + .60(30) = .30(x+30)
.20x + 18 = .30x + 9
18 - 9 = .30x - .20x
9 = .10x
x = 9%2F.1
x = 90 liters of 20% solution
:
:
See if this is true
.2(90) + .6(30) = .3(90+30)
18 + 18 = .3(120); confirms our solutio