SOLUTION: A chemist needs 130 milliliters of a 28% solution but has only 19% and 58% solutions available. Find how many milliters of each that should be mixed to get the desired solution.

Question 227994: A chemist needs 130 milliliters of a 28% solution but has only 19% and 58% solutions available. Find how many milliters of each that should be mixed to get the desired solution.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A chemist needs 130 milliliters of a 28% solution but has only 19% and 58% solutions available.
Find how many milliliters of each that should be mixed to get the desired solution.
:
Let x = amt of 58% solution
It say's the amt of the resulting mixture is to be 130 ml, therefore
(130-x) = amt of 19% solution
:
A typical mixture equation
:
.58x + .19(130-x) = .28(130)
:
.58x + 24.7 - .19x = 36.4
:
.58x - .19x = 36.4 - 24.7
:
.39x = 11.7
x =
x = 30 ml of 58% solution required
and
130 - 30 = 100 ml of 19% solution
;
:
Check solution in original mixture equation
.58(30) + .19(100) = .28(130)
17.4 + 19 = 36.4
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