SOLUTION: How many millimeters of pure acid must be added to 120 milliliters of a 30% acid solution to obtain a 50% solution?
Algebra.Com
Question 227284: How many millimeters of pure acid must be added to 120 milliliters of a 30% acid solution to obtain a 50% solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.30*120+x=.50(120+x)
36+x=60+.5x
x-.5x=60-36
.5x=24
x=24/.5
x=48 ml of pure acid is used.
Proof:
.30*120+48=.5(120+48)
36+48=.5*168
84=84
RELATED QUESTIONS
How many milliliters of pure acid must be added to 150 milliliters of a 30% acid solution (answered by stanbon)
How many milliliters of a 40% acid solution must be added to 150 milliliters of a 65%... (answered by ptaylor)
A chemist has 10 millimeters of a solution that contains a 30% concentration of acid. How (answered by solver91311)
How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of... (answered by stanbon)
How many milliliters of pure acid must be added to 150 milliliters of a 70% solution of... (answered by robertb)
How many milliliters of pure acid must be added to 100 milliliters of a 10% acid solution (answered by ptaylor)
How much pure hydrocloric acid must be added to 40 milliliters of a 50% solution to... (answered by Fombitz)
How much pure hydrocloric acid must be added to 40 milliliters of a 50% solution to... (answered by stanbon)
My problem is as follows:
How much pure hydrocloric acid must be added to 40 milliliters (answered by lwsshak3)