SOLUTION: What quantity of 75 per cent acid solution must be mixed with a 30 percent solution to produce 1215 mL of a 50 per cent solution?

Algebra.Com
Question 226639: What quantity of 75 per cent acid solution must be mixed with a 30 percent solution to produce 1215 mL of a 50 per cent solution?
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
.75x+.30(1215-x)=.50*1215
.75x+364.5-.30x=607.5
.75x-.30x=607.5-364.5
.45x=243
x=243/.45
x=540 ml of 75% acid.
1215-540=675 ml of 30% acid.
Proof:
.75*540+.30*675=.50*1215
405+202.5=607.5
607.5=607.5

RELATED QUESTIONS

What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to... (answered by stanbon)
(1 pt) What quantity of 65 per cent acid solution must be mixed with a 30 percent... (answered by josmiceli)
What quantity of 75 per cent acid solution must be mixed with a 25 per cent solution to... (answered by josmiceli)
What quantity of 75 per cent acid solution must be mixed with a 20 per cent solution to... (answered by josgarithmetic,MathTherapy)
What quantity of 60 per cent acid solution must be mixed with a 30 per cent solution to... (answered by modi.kk91)
What quantity of 75 per cent acid solution must be mixed with a 25 solution to produce... (answered by rfer)
What quantity of 70 per cent acid solution must be mixed with a 20 percent solution to... (answered by checkley77)
What quantity of 60 per cent acid solution must be mixed with a 25 percent solution to... (answered by Alan3354)
What quantity of 60 per cent acid solution must be mixed with a 20 percent solution to... (answered by jrfrunner)