SOLUTION: A 3% solution of sulfuric acid was mixed with an 18% solution to produce an 8% solution. how much 3 % solution and 18% solution were used to produce 15 liters of 8% solution?
Algebra.Com
Question 225668: A 3% solution of sulfuric acid was mixed with an 18% solution to produce an 8% solution. how much 3 % solution and 18% solution were used to produce 15 liters of 8% solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.18X+.03(15-X)=.08*15
.18X+.45-.03X=1.2
.15X=1.2-.45
.15X=.75
X=.75/.15
X=5 lITERS OF 18% SOLUTION IS USED.
15-5=10 lITERS OF 3% SOLUTION IS USED.
PROOF:
.18*5+.03*10=.08*15
.9+.3=1.2
1.2=1.2
RELATED QUESTIONS
A 3% solution of sulfuric acid was mixed with an 18% solution of sulfuric acid to produce (answered by checkley79)
A 2% solution of sulfuric acid was mixed with a 12% solution of sulfuric acid to produce... (answered by richwmiller)
3. A chemist mixed a solution that was 34% acid with another solution that was 18% acid... (answered by math_tutor2020)
how many milliliters of a 20% acid solution should be mixed with 50 ml of an 8% acid... (answered by josgarithmetic)
how much of a 25% acid solution must be mixed with 4 gallons of an 18% acid solution to... (answered by stanbon)
How many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24%... (answered by nerdybill)
How much of an 18% solution of sulfuric acid should be added to 360 mL of a 10% solution... (answered by richwmiller)
How much of an 18% solution of sulfuric acid should be added to 380ml of a 10% solution... (answered by mananth)
how many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24%... (answered by mananth)