SOLUTION: A chemist wants to mix a 60% saline solution with 20 liters of a 45% saline solution to obtain a 55% saline solution. How much of the 60% solution should she use?
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Question 224686: A chemist wants to mix a 60% saline solution with 20 liters of a 45% saline solution to obtain a 55% saline solution. How much of the 60% solution should she use?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.80*20+.45x=.55(20+x)
16+.45x=11+.55x
.45x-.55x=11-16
-.10x=-5
x=-5/-.1
x=50 liters of 60% solution is used.
Proof:
.80*20+.45*50=.55(20+50)
16+22.5=.55*70
38.5=38.5
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