SOLUTION: A car's radiator contains 12L of antifreeze at 25% concentration. How many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%?
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Question 222797: A car's radiator contains 12L of antifreeze at 25% concentration. How many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A car's radiator contains 12L of antifreeze at 25% concentration. How many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%?
.
Let x = amount removed and replaced w/pure antifreeze
then
x + .25(12-x) = .50(12)
x + 4 - .25x = 6
x - .25x = 2
.75x = 2
x = 2/.75
x = 2.67 liters
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