SOLUTION: Please help me solve this problem:
How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? use t
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Question 219856: Please help me solve this problem:
How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? use the six step method
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of
25% antifreeze to get a mixture that is 60% antifreeze?
use the six step method
;
I'm not sure what the six step method, but this is how I would do it
:
Let x = amt of 70% solution will be required
:
A simple mixture equation
.70x + .25(70) = .60(x + 70)
:
.70x + 17.5 = .60x + 42
:
.70x - .60x = 42 - 17.5
:
.10x = 24.5
x =
x = 245 gal of 70% solution
:
:
Check solution in the original equation
.70(245) + .25(70) = .60(245 + 70)
171.5 + 17.5 = .60(315)
189 = 189
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