SOLUTION: Hi, I have a solution/miture question. I can solve the problem just fine once I get it in the right order... but this one I'm having a hard time putting all the info where it belon

Question 219575: Hi, I have a solution/miture question. I can solve the problem just fine once I get it in the right order... but this one I'm having a hard time putting all the info where it belongs.
Q) A pharmacist has 20L of a 10% drug solution. How many liters of 5% solution must be added to get a mixture that is 8%?
If you could just help me get this in the right format I would would be so thankful!! Thanks!!!
Casie R
Found 2 solutions by RAY100, josmiceli:
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let x= amt added in liters
.
.1(20) + .05x = .08(20+x),,,drug amt,,,,,note total volume is x+20
.
.(2) +.05x = 1.6 + .08x
.
.(.4) = .03 x
.
13.33333 = x in liters
.
.
check,,,.1*20 +.05*13.33333= .08*33.33333
.
2+.667 = 2.6667,,,ok
.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = liters of 5% solution to be added
It doesn't say what the drug is mixed with, so I'll
just call it water.
In words:
(liters of drug in final solution)/(liters of drug + water in final solution) = 8%
given:
In liters of 10% solution, there is
liters of drug
In liters of the 5% solution there is
liters of drug
-------------------------

The Pharmacist must add 13.333 liters of the 5% solution
check answer

(error due to rounding -OK)

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