# SOLUTION: A lab has a 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution?

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 Click here to see ALL problems on Mixture Word Problems Question 217064: A lab has a 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution?Answer by nerdybill(6958)   (Show Source): You can put this solution on YOUR website! A lab has a 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution? . Let x = liters of 20% acid solution then 600-x = liters of 50% acid solution . .20x + .50(600-x) = .30(600) .20x + 300 - .50x = 180 300 - .30x = 180 300 = .30x + 180 120 = .30x 400 liters = x (amount of 20% acid solution) . Amount of 50% acid solution: 600-x = 600-400 = 200 liters