# SOLUTION: How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution?

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 Question 216452: How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution?Answer by nerdybill(6957)   (Show Source): You can put this solution on YOUR website! How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution? . Let x = liters of 60% acid solution to be added then 20-x = liters of 75% acid solution to be added . Our equation: .60x + .75(20-x) = .72(20) .60x + 15 - .75x = 14.4 15 - .15x = 14.4 - .15x = -.6 x = 4 L (60% solution) . 75% solution: 20-x = 20-4 = 16 L