SOLUTION: How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 liters of an 85% gasoline mixture?

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Question 216315: How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 liters of an 85% gasoline mixture?
Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
0.90x+.75(600-x)=.85*600
.90x+450=.75x=510
.90x-.75x=510-450
.15x=60
x=60/.15
x=400 gallons of 90% gas is used.
600-400=200 gallons of 75% gas is used.
Proof:
.90*400+.75*200=.85*600
360+150=510
510=510