SOLUTION: I am having a hard time trying to figure this problem out. It would be greatly appreciated if you could assist me. This question is from a work book not the text book:
Brass i
Algebra.Com
Question 214314: I am having a hard time trying to figure this problem out. It would be greatly appreciated if you could assist me. This question is from a work book not the text book:
Brass is an alloy made up of copper and zinc in varying proportions. How much brass containing 75.5% copper must be combined with a different brass containing 86.3% copper to make 5250kg of brass containing 80.0% copper
Thanks so much,
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Brass is an alloy made up of copper and zinc in varying proportions. How much brass containing 75.5% copper must be combined with a different brass containing 86.3% copper to make 5250kg of brass containing 80.0% copper
--------------------------------------
Equation:
copper + copper = copper
0.755x + 0.863(5250-x) = 0.80*5250
--------------------------------------
Multiply thru by 1000 to get:
755x + 863*5250 - 863x = 800*5250
-108x = -63*5250
x = 3062.5 kg (amt. of 75.5% copper in the mixture)
---
5250-3062.5 = 2187.5 kg (amt of 86.3% copper in the mixture)
==========================
Cheers,
Stan H.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
One way to approach these kinds of problems is to write down the amounts of copper (Cu) there are in the different brass alloys. Let x = the amount of the brass with 75.5% Cu.
The amount of amount of Cu in x kgs of this alloy can be expressed as:
kg of Cu.
The amount of Cu in the other 86.3% Cu-brass alloy can be expressed as:
kg. of Cu.
The sum of these two amounts is to equal 5250 kg of 80% Cu-brass.
So we can write the equation to find x.
Simplify and solve for x.
Subtract 4530.75 from both sides.
Divide both sides by -0.108
kg of the brass with 75.5% Cu.
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