SOLUTION: How many grams of silver that is 60% pure must be mixed together with silver that is 35% pure to obtain a mixture of 90 grams of silver that is 45% pure?

SOLUTION: How many grams of silver that is 60% pure must be mixed together with silver that is 35% pure to obtain a mixture of 90 grams of silver that is 45% pure?

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Question 211529: How many grams of silver that is 60% pure must be mixed together with silver that is 35% pure to obtain a mixture of 90 grams of silver that is 45% pure?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
60%=x=36 gr
35%=90-x=54 gr
.6x+.35(90-x)=.45*90
.6x+31.5-.35x=40.5
.25x=9
x=36
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