SOLUTION: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
Algebra.Com
Question 208928: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let x = additive volume in liters
.
.40*x + .80*10 = .60*(10+x)
.
.4x +8 = 6 + .6x
.
2=.2x
.
10=x
.
check
.4*10 +.8*10 = .6 *(10+10)=12,,,,ok
.
RELATED QUESTIONS
How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by ankor@dixie-net.com)
how many liters of a 40% alcohol solution must be mixed with 10 liters of a solution... (answered by Alan3354)
How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by checkley77)
How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that (answered by nyc_function)
how many liters of a 10 percent alcohol solution must be mixed with 70 liters of the... (answered by mananth)
how many liters of a 10% alcohol solution must be mixed with how many liters of a 50%... (answered by mananth)
How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by Fombitz,edjones)
How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution... (answered by richwmiller)
how many liters of a 20% alcohol solution must be mixed with 30 liters of a 80% solution... (answered by robertb)