SOLUTION: The combined cost of one advance ticket and one same-day ticket to a show was $55. It is known that 15 tickets were sold in advance and 30 the same day, for total receipts of $1050

Question 208258: The combined cost of one advance ticket and one same-day ticket to a show was $55. It is known that 15 tickets were sold in advance and 30 the same day, for total receipts of $1050 . What was the price of each kind of ticket?

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x+y=55 or x=55-y
15x+30y=1050
15(55-y)+30y=1050
825-15y+30y=1050
15y=1050-825
15y=225
y=225/15
y=15 number of same day tickets were sold.
x+15=55
x=55-15
x=40 advance tickets sold.
Proof:
15*40+30*15=1050
600+450=1050
1050=1050
RELATED QUESTIONS
Suppose that there are two types of tickets to a show: advance and same-day. The combined (answered by josgarithmetic)

The combined cost of one advance ticket to a show and one same-day ticket was $55. It is... (answered by Paul)

The combined cost of one advance ticket to a show and one same-day ticket was $55 . It is (answered by checkley71,stanbon)

Suppose that there are two types of tickets to a show: advance and same-day. The combined (answered by josgarithmetic,greenestamps)

Suppose that there are two types of tickets to a show. Advance and same day. The combined (answered by ikleyn)

Suppose that there are two types of tickets to a show: advance and same-day. The combined (answered by josgarithmetic)

Suppose that there are two types of tickets to a show: advance and same-day. The combined (answered by Theo,ikleyn)

Suppose that there are two types of tickets to a show: advance and same-day. The combined (answered by josgarithmetic)