SOLUTION: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?
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Question 198833: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
(mg of nickel) / (mg of alloy) = 78%
Let = mgs of metal with 45% nickel
4 mg of the metal must be used
check:
OK
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